2y-y^2-8=0

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Solution for 2y-y^2-8=0 equation:


Simplifying
2y + -1y2 + -8 = 0

Reorder the terms:
-8 + 2y + -1y2 = 0

Solving
-8 + 2y + -1y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
8 + -2y + y2 = 0

Move the constant term to the right:

Add '-8' to each side of the equation.
8 + -2y + -8 + y2 = 0 + -8

Reorder the terms:
8 + -8 + -2y + y2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -2y + y2 = 0 + -8
-2y + y2 = 0 + -8

Combine like terms: 0 + -8 = -8
-2y + y2 = -8

The y term is -2y.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2y + 1 + y2 = -8 + 1

Reorder the terms:
1 + -2y + y2 = -8 + 1

Combine like terms: -8 + 1 = -7
1 + -2y + y2 = -7

Factor a perfect square on the left side:
(y + -1)(y + -1) = -7

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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